/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> ans;
vector<int>path;
void dfs(TreeNode* root, int targetSum){
if(root==nullptr)return;
path.emplace_back(root->val);
targetSum-=root->val;
if(root->left==nullptr&&root->right==nullptr&&targetSum==0){
ans.emplace_back(path);
}
dfs(root->left,targetSum);
dfs(root->right,targetSum);
path.pop_back();
}
vector<vector<int>> pathSum(TreeNode* root, int targetSum) {
dfs(root,targetSum);
return ans;
}
};